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-48x^2+240x+0=0
We add all the numbers together, and all the variables
-48x^2+240x=0
a = -48; b = 240; c = 0;
Δ = b2-4ac
Δ = 2402-4·(-48)·0
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{57600}=240$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(240)-240}{2*-48}=\frac{-480}{-96} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(240)+240}{2*-48}=\frac{0}{-96} =0 $
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